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MArishka [77]
3 years ago
12

The points (–7, 7) and (6, –6) fall on a particular line. What is its equation in slope-intercept form?

Mathematics
2 answers:
AURORKA [14]3 years ago
5 0

Answer:

y= -x

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept

\boxed{slope =  \frac{y1 - y2}{x1 - x2} }

Slope

=  \frac{7 - ( - 6)}{ - 7 - 6}

=  \frac{7 + 6}{ - 13}

=  \frac{13}{ - 13}

=  - 1

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

alexandr1967 [171]3 years ago
3 0

Answer:

y=-x

Step-by-step explanation:

Slope =1

Substitute m= -1 into the equation:

y= -1x +c

y= -x +c

To find the value of c, substitute a pair of coordinates.

When x= -7, y= 7,

7= -(-7) +c

7= 7 +c

c= 7 -7

c= 0

Thus, the equation of the line is y= -x.

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