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vesna_86 [32]
3 years ago
13

Someone please explain the difference of Multiples and Factors as well as an example. ​

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

A multiple is a number that can be divided by another number a certain number of times without a remainder. A factor is one of two or more numbers that divides a given number without a remainder.

Example:

2 is a factor of 8.

8 is a multiple of 2.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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Sanford's gym coach made him run 20 laps on a 400 m track. How many kilometers did he run? How many miles?
Andrej [43]

Answer:

8km  5mi

Step-by-step explanation:

20x400=8000meters a km = to 1000meters

8000/1000=8km

A mile is a kilometer/ 1.6  8/1.6=5 miles

8 0
2 years ago
PLEASE HELP ME WITH:
True [87]
B.  If square-foot is on the x-axis then we can substitute for x in the equation and solve, and when we do, we get 2473.302 which is is B when rounded. 
8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%
Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

The domain refers to all values of x for which the function is defined.

The function is defined for

x^4+x^3-4x^2-4\ne0

This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0
3 years ago
(4x^3 - x^2 +4x) + (x^3 -x^2 - 4x)
madreJ [45]

Answer:

5x³ - 2x²

Step-by-step explanation:

Step 1: Write out expression

4x³ - x² + 4x + x³ - x² - 4x

Step 2: Combine like terms (x³)

5x³ - x² + 4x - x² - 4x

Step 3: Combine like terms (x²)

5x³ - 2x² + 4x - 4x

Step 4: Combine like terms (x)

5x³ - 2x²

4 0
3 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
2 years ago
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