In order for the inverse to exist, the matrix cannot be singular, so we need to first examine the conditions for existence of the inverse.
Compute the determinant. The easiest way might be a cofactor expansion along either the first row or third column; I'll do the first.
The matrix is then singular whenever
.
With this in mind, compute the inverse.
Answer:
speed is 35 I think it is answer
Answer:
-1/6 + 8
Step-by-step explanation:
(1/2x + 2) - (2/3x - 6)
apply distributive property
1/2x + 2 - 2/3x + 6
add like terms. add 1/2x and -2/3x together and then add 2 and 6 together
3/6 + 2 - 4/6 + 6
-1/6 + 8
-1/6 + 8 is your answer. i hope this helps, let me know if i got something wrong :)
Since each odd (or even) is two greater than the previous number, two consecutive such numbers are n and n+2.
The we are told that the sum of two such number is 100, so we can say:
n+n+2=100 combining like terms on the left side you get:
2n+2=100
....
to solve, if you were interested...subtract 2 from both sides
2n=98 divide both sides by 2
n=49
So the two odd numbers are 49 and 51
Answer:
DE = 21
Step-by-step explanation:
Recall: the ratio of the corresponding side lengths of similar triangles are equal
Given that ∆ABC ~ ∆DEF, therefore,
AB/DE = BC/EF = AC/DF
AB = 8.4
DE = x
BC = 10
EF = 25
AC = 16.5
DF = 41.25
Let's find DE using AB/DE = BC/EF. Thus:
8.4/x = 10/25
Cross multiply
x*10 = 25*8.4
10x = 210
Divide both sides by 10
x = 210/10
x = 21
DE = x = 21