A train 100 m long crosses a pole in 5 seconds.Find the speed of the train in kilometre per hour.

Mathematics

1 answer:

In-s [12.5K]2 years ago

6 0

Answer:

$\sf72 km/h$

Step-by-step explanation:

Distance covered by the train in crossing the pole = 100 m.

$\sf Time \: taken=5 \: seconds$

$\sf \: Speed \: of \: the \: train = \frac{Distance }{Time}$

$\sf = \frac{100}{5} \: m/s$

$\sf \: = 20 \: m/s$

$\sf \: = 20 \times \frac{18}{5} \: km/h$

$\sf = 72 \: km/h$

Hence, the speed of the train is 72 km/h

You might be interested in

The sum of two numbers is 46 . the larger number is 12 more than the smaller number. what are the numbers?

snow_tiger [21]

X + y = 46
x = y + 12

y + 12 + y = 46
2y + 12 = 46
2y = 46 - 12
2y = 34
y = 34/2
y = 17

x = y + 12
x = 17 + 12
x = 29

so ur 2 numbers are : 29 and 17

4 0

2 years ago

Read 2 more answers

Which of the following coordinates is farthest to the right of the origin on a coordinate plane?

KatRina [158]

Where’s the picture

5 0

2 years ago

Read 2 more answers

Solve the system by substitution. y = -4x 23 - 5y = 44

spin [16.1K]

<h3>Explanation</h3>

Given the system of equations.

$\begin{cases} y = - 4x \\ 23 - 5y = 44 \end{cases}$

Substitute y = -4x in the second equation.

$23 - 5( - 4x) = 44 \\ 23 + 20x = 44 \\ 20x = 44 - 23 \\ 20x = 21 \\ x = \frac{21}{20}$

Substitute the value of x in any given equations. I will substitute the value of x in the first equation.

$y = - 4x \Longrightarrow y = - 4( \frac{21}{20} ) \\ y = \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \Longrightarrow y = - \frac{21}{5} \\ y = - \frac{21}{5}$

Answer Check by substituting both values in two equations.

First Equation

$y = - 4x \Longrightarrow - \frac{21}{5} = - 4( \frac{21}{20} ) \\ - \frac{21}{5} = \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \\ - \frac{21}{5} = - \frac{21}{5} \: \: \: \checkmark$