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Elina [12.6K]
1 year ago
15

Does this graph represent a function?

Mathematics
1 answer:
murzikaleks [220]1 year ago
4 0

The graph doesn't represent a function

f(x) 3 because D. Yes, because each x-value has exactly one corresponding y-value.

<h3>What is a function?</h3>

It should be noted that a function simply assigns the value of each element of a particular set to the other specific element of another set.

It can be seen that in the given graph, each specific value of x from the x-axis represents a value on the y-axis. Therefore, it can be concluded that the given graph is a function because each x-value has exactly one corresponding y-value.

Learn more about graph on:

brainly.com/question/19040584

#SPJ1

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Please help me with this I need this done!!!
mote1985 [20]

Answer:

1=1

2=4

3= <NTR=115

   <RTM=45

  <STN=45

4= A-124

    B-45

    C-45

    D-90

    E-124

5=15

6=?

Step-by-step explanation:

FGHJK

8 0
3 years ago
2y-____=0;y=0 HELPPPPPPP
AVprozaik [17]

Answer:

<em>D.)  0</em>

Step-by-step explanation:

Its not A.  cause 2y−2=0  is y = 1

Its not B. cause 2y−1=0  is y = 1/2

Its not C. cause 2y−3=0  is y = 3/2

Soo... The only option left is D.

It IS D. cause 2y − 0 = 0  is y=0

<em>So you are Correct!!!</em>

<em>hope I helped... <3</em>

<em>Good luck dear :)</em>

4 0
3 years ago
Examine the following graph of y=−3x+7.
likoan [24]
Y=7
X=-3
The following graph
8 0
3 years ago
Sara was making slug slime soup for her six friends. She needed 0.06
Marina86 [1]

Answer:

0.01

can I have brainliest please

Step-by-step explanation:

3 0
2 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
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