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Ipatiy [6.2K]
3 years ago
14

Simplify 6-sqr25/4=..............

Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

7/2 is the correct answer

Step-by-step explanation:

In pic

(credit symbolab)

(Hope this helps can I pls have brainlist (crown) ☺️)

Mkey [24]3 years ago
3 0

6 -  \sqrt{ \frac{25}{4} }  \\  = 6 -  \frac{5}{2}  \\  =  \frac{12 - 5}{2}  \\  =  \frac{7}{2}  \\  = 3.5

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The set of ordered pairs represents a functuon. Write a rule represents the function. (0,0),(1,6),(2,24),(3,54),(4,96)
Lubov Fominskaja [6]
It’s super self explanatory it’s right there
3 0
3 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
11 months ago
2.1e-10 in standard form?
just olya [345]
<span>2.1e-10
= 2.1 x 10^-10
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3 years ago
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Vsevolod [243]
....the answer is -8,8
6 0
3 years ago
Read 2 more answers
Solve this please!!!
Pani-rosa [81]
I attached a couple below pictures with all the work and a bit more information to help you understand the problem.
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5 0
3 years ago
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