so the company has an overhead of $600, usually that involves premises leasing and industrial equipment for the manufacturing of the product, that's cost. The cost to make each item is 50 cents, so if the company produces "x" items, their cost is 0.5x total.
so our cost equation C(x) = 0.5x + 600 <---- items' cost plus overhead.
the company sells the product for 85 cents, so if they sell "x" items, their total revenue or income will be 0.85x.
so our revenue equation is simply R(x) = 0.85x.
as you already know, the break-even point is when.... well, you break even, no losses but no gains either, how much you take in is the same amount that you shelled out, namely R(x) = C(x).
Add 8 on both sides in order to isolate n:
-3 + 8 < n - 8 + 8
5 < n
The area of a kite is (1/2) * x * y, where x and y are the length of the two diagonals. In this case, the length of the two diagonals are 10 ft and 2 ft.
<span>Plug that in the equation, we get 1/2 * 2 * 10. We multiply the 2 and 10 first to get 20, that leaves us with 1/2 x 20, which is 10, so the area of this kite is 10 ft squared.</span>
The answer will be x^3-5. Hope it help!
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes
(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)
Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes
(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%
With actual average time to walk to the bus stop being 10 minutes;
(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes
(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.
(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0
From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
