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V125BC [204]
2 years ago
5

Which counterexample can be used to show that the following conjecture is false?

Mathematics
1 answer:
vitfil [10]2 years ago
7 0

1and2 are supplementary angles is conjecture is false

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HELP DUE IN 5 MINUTES
Dafna1 [17]

Answer:

100C=m

Step-by-step explanation:

If 250 copies are made in 2.5 minutes, you get the equation:

250c=2.5m

divide by 2.5 on both sides and you get:

100c=m

So in m minutes, 100c copies are made.

7 0
3 years ago
If k(x) = 2x² -3.Vx, then k(9) is
Alexus [3.1K]

Answer:

159

Step-by-step explanation:

k (9) = (2 * 9^{2}) - 3

= (2 * 81) - 3

= 162 - 3

= 159

8 0
3 years ago
HELP I WILL GIVE BRAINLEIST OR WHATEVER 50 POINTS​
Ilya [14]

answer:

a. scarf costs today = $6

b. scarf costs 3 days from now = $3

step-by-step explanation:

  • 1/2 off means you would multiply the amount by 1/2 then subtract

a. original price of scarf: $12

12 X 1/2 = 6

12 - 6 = 6

— scarf costs today = $6

  • do the same thing but this time it is a different number

b. 12 X 3/4 = 9

12 - 9 = 3

— scarf costs 3 days from now = $3

3 0
3 years ago
Write a biconditional statement to define the term parallelogram
son4ous [18]
In Euclidean geometry, a parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.



Hope this helps :)
6 0
3 years ago
tensor-on-tensor regression: riemannian optimization, over-parameterization, statistical-computational gap and their interplay
Contact [7]

The purpose of the tensor-on-tensor regression, which we examine, is to relate tensor responses to tensor covariates with a low Tucker rank parameter tensor/matrix without being aware of its intrinsic rank beforehand.

By examining the impact of rank over-parameterization, we suggest the Riemannian Gradient Descent (RGD) and Riemannian Gauss-Newton (RGN) methods to address the problem of unknown rank. By demonstrating that RGD and RGN, respectively, converge linearly and quadratically to a statistically optimal estimate in both rank correctly-parameterized and over-parameterized scenarios, we offer the first convergence guarantee for the generic tensor-on-tensor regression. According to our theory, Riemannian optimization techniques automatically adjust to over-parameterization without requiring implementation changes.

Learn more about tensor-on-tensor here

brainly.com/question/16382372

#SPJ4

7 0
2 years ago
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