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2 years ago

Solve for X 50 points in it for you plus a thanks, 5 star rating and brainliest!

Mathematics

2 answers:

Wewaii [24]2 years ago

5 0

Answer:

X=5

Step-by-step explanation:

hope this helps:)

Misha Larkins [42]2 years ago

3 0

First in ∆KLM

$\\ \sf\longmapsto LM^2=32^2-15^2=992-225$

$\\ \sf\longmapsto LM^2=767$

Now

$\\ \sf\longmapsto LM^2=KM\times JM$

$\\ \sf\longmapsto 767=15(x-15)$

$\\ \sf\longmapsto 15x-225=767$

$\\ \sf\longmapsto 15x=767+225=992$

$\\ \sf\longmapsto x=\dfrac{992}{15}$

$\\ \sf\longmapsto x=66$

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Dylan opens a credit card account with $550.00 of available credit .Now that he has made some purchases Dylan’s account only has

Goryan [66]

Answer:

I'm pretty sure it's C

Step-by-step explanation:

the calculations I did, C was the closest

4 0

3 years ago

Maths trig functions <br> please help

Nikitich [7]

1. According to the plots, the curves intersect when $x=90^\circ$ and $x=360^\circ$ .

We can confirm this algebraically.

$\sin(x) + 2 = -\cos(x) + 3$

$\sin(x) + \cos(x) = 1$

$\sqrt2 \sin\left(x + 45^\circ\right) = 1$

$\sin\left(x + 45^\circ\right) = \dfrac1{\sqrt2}$

$x + 45^\circ = \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n \text{ or } x + 45^\circ = 180^\circ - \sin^{-1}\left(\dfrac1{\sqrt2}\right) + 360^\circ n$

(where $n$ is an integer)

$x + 45^\circ = 45^\circ + 360^\circ n \text{ or } x + 45^\circ = 135^\circ + 360^\circ n$

$x = 360^\circ n \text{ or } x = 90^\circ + 360^\circ n$

We get the two solutions we found in the interval [0°, 360°] with $n=1$ in the first case, and $n=0$ in the second case.

2. We have $\sin(x)=0$ when $x \in \{0^\circ, \pm 180^\circ, \pm360^\circ, \ldots\}$ . For the given plot domain [0°, 360°], this happens when $180^\circ < x < 360^\circ$ .