Answer:
TU=4
Step-by-step explanation:
WU cuts the triangle in half (hint- angleTUW=90°)
so VU=TU
therefore, TU=4
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
9514 1404 393
Answer:
P(B) = 0.65
Step-by-step explanation:
The appropriate formula is ...
P(A or B) = P(A) +P(B) -P(A and B)
Then P(B) is ...
P(B) = P(A or B) +P(A and B) -P(A)
P(B) = 0.8 +0.15 -0.3
P(B) = 0.65
-4m +18-6=0
-4m+12=0
-4m=-12
m=3
Answer:
320
Step-by-step explanation:
Using the rules of exponents
• 
⇔ 
• 
× ⇔ 
simplifying 
= 4³ × x³ = 64x³
(5x³) ×
= 5x³ × 64x³ = (5 × 64) × (x³ × x³) = 320
= 320
