Using implicit differentiation, it is found that the radius is increasing at a rate of 0.0081 cm per minute.
<h3>What is the volume of a sphere?</h3>
The volume of a sphere of radius r is given by:

Applying implicit differentiation, the rate of change is given by:

In this problem, we have that:

Hence the rate of change of the radius is given as follows:




The radius is increasing at a rate of 0.0081 cm per minute.
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Answer:
6
Step-by-step explanation:
I used the formula d=√((x_2-x_1)²+(y_2-y_1)²), plugged in the numbers and solved and got 6 units.
f(x) = 5x − 1 and g(x) = 2x^2 + 1
(f × g)(x) = (5x − 1)(2x^2 + 1)
(f × g)(x) = 10x^3 - 2x^2 + 5x - 1
Substitute x = - 3
(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1
(f × g)(-3) = 10(-27) - 2(9) -15 - 1
(f × g)(-3) =-270 - 18 - 16
(f × g)(-3) = -236
Answer
- 236