The question wants us to find 3 times the volume of the pool.
This is because we are told that the pool must be filled 3 times during the summer and asked how many cubic feet of water is required to fill the pool all summer.
Step 1: Find the volume of the pool.
Volume is calculated by multiplying length by width by height.
Pool length = 5 ft.
Pool width = 4 ft.
Pool height = 2 ft.
Pool volume = 5 • 4 • 2
5 • 4 • 2 = 40
The volume of the pool is 40 cubic feet.
Step 2: Find 3 times the volume of the pool.
Volume = 40 ft.^3
3 times volume = 3 • 40 ft.^3
3 • 40 ft.^3 = 120 ft.^3
3 times the volume of the pool is 120 cubic feet.
Answer:
The pool requires 120 cubic feet of water in order to be filled enough over the course of the summer.
Hope this helps!
Answer:
Step-by-step explanation:
The basic cost of the Snout is 45.99
15% of that amount = 45.99*15/100 = <u> 6.90</u>
Total Cost 52.89
You could figure out the total cost a slightly different way.
You could set up
Cost = snout (1 + 15%)
Cost = snout(1 + 15/100)
Cost = snout( 1 + 0.15)
Cost = 45.99(1.15)
Cost = 52.89
Gio should for sure devide everything by ^2 and then combine like terms.
A_n= a₁+(n-1)d
a₁ first term
n terms
d distance between each value
a_n= 12+(405-1)(5)=2032
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
