Well the answer is 14 cm, because all you have to do is divide the length of LN in half
Answer:
thx
Step-by-step explanation:
Use the equation .8x + x = 252
x is the number, and .8 is the decimal equivalent of 80%.
1.8x = 252
x = 140
Answer:
The work done to pump all of the kerosene from the tank to an outlet is
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :
![dF=\pi R^{2}dy*50](https://tex.z-dn.net/?f=dF%3D%5Cpi%20R%5E%7B2%7Ddy%2A50)
This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.
![W=450\pi \int_{0}^{8}dy(8-y)](https://tex.z-dn.net/?f=W%3D450%5Cpi%20%5Cint_%7B0%7D%5E%7B8%7Ddy%288-y%29)
![W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)](https://tex.z-dn.net/?f=W%3D450%5Cpi%28%5Cint_%7B0%7D%5E%7B8%7D%208dy-%5Cint_%7B0%7D%5E%7B8%7D%20ydy%29)
![W=450\pi(8*8 -\frac{8^{2}}{2})](https://tex.z-dn.net/?f=W%3D450%5Cpi%288%2A8%20-%5Cfrac%7B8%5E%7B2%7D%7D%7B2%7D%29)
![W=450\pi(64 -\frac{64}{2})](https://tex.z-dn.net/?f=W%3D450%5Cpi%2864%20-%5Cfrac%7B64%7D%7B2%7D%29)
Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
By adding 3 to both sides and dividing both sides of the equation by 4 you end up with x=6
answer is x =6
Hope this helps!!