Please help I need to pass Mac

A school ordered a trapezoidal activity table as shown in the figure. Find the area of the table. SHOW ALL

vredina [299]

Answer:

A=630 in^2

Step-by-step explanation:

Triangles: there are two equal triangles so we can treat them as one rectangle

A = 15 * 14 = 210

Rectangle:

A=30 * 14 = 420

A_total = 210 + 420 = 630 in^2

6 0

3 years ago

Sam wants to find the best buy on cans of tuna. He reads these four ads in the newspaper. Place the ads in order from best to wo

Mamont248 [21]

Best to worst;

8.34/6 = $1.39

7.95/5 = $1.59

12.53/7 = $1.79

5.97/3 = $1.99

7 0

3 years ago

Read 2 more answers

See image attached below keeeeeeeeeeeeeeeeeeeed

emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1 whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1 whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0

3 years ago

1. What does it mean that Nikoleta is in the 10th percentile for length and weight? Is that a desirable statistic if she was in

VladimirAG [237]

Explanation:

1. It means that Nikoleta is longer and heavier than 10% of children her age.

2. We generally expect that a change from being in the 50th percentile to the 10th percentile signifies a condition that is interfering with normal growth. That is not usually considered desirable.

5 0

4 years ago

Read 2 more answers

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 − 1)3, [−1, 2]

Alja [10]

Given :

$F(x)=3(x^2-1)$

To Find :

the absolute minimum and absolute maximum values of f on the given interval

[-1,2] .

Solution :

Now , getting first order differential equation and equating its equal to zero.

$\dfrac{d(3x^2-3)}{dx}=0\\\\6x=0\\x=0$

So , x=0 is critical point .

Now , coefficient of $x^2$ is positive .

Therefore , it is increasing function after x=0 .

So , min value will be at , x=0.

$Min = (0^2-1)\times 3=-3$

And maximum value will be the maximum at the x=2 because it is increasing function .

$Max=(2^2-1)\times 3=9$

Therefore , max and min value is 9 and -3 respectively .

Hence , this is the required solution .

3 0

3 years ago