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MakcuM [25]
3 years ago
12

2.5.2 Project:Performance Task:A trade show booth

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

2162203625

12345

joín on Zóôm

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Determine the number of crawlers and rovers to make,that will maximize the company profit in a given week
Dmitriy789 [7]

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jjjijijijiiijijijijijijij no pliss inglés. ;D.

8 0
2 years ago
6x+5y+2z=41<br> 4x-10z=-10<br> -x-2y+2z=-1
Rasek [7]
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​]
3 0
3 years ago
An angle is 6 more than five times its supplement. Find the measure of the largest angle.
Julli [10]
Supplementary angles add up to 180°


Angle y is the large angle: y= 5x+6

180= x+y
180= (5x+6) + x
180=6x+6
174=6x
x=29

180= y+29
y=151°
4 0
3 years ago
Read 2 more answers
Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.
Katena32 [7]

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle (A), measured in square inches, is directly proportional to the square of its diameter (d), measured in inches. That is:

A \propto d^{2}

A = k\cdot d^{2}

Where k is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}

The area of the circle B is now cleared:

A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}

Given that d_{A} = 20\,in, d_{B} = 60\,in and A_{A} = 300\,in^{2}, then:

A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})

A_{B} = 2700\,in^{2}

Therefore, the correct answer is 4.

7 0
3 years ago
Lori has 60% of the book to read. If she has read 120 pages how many pages does she still have to read
maks197457 [2]
Ok, so 120 pages plus the 60% of the book she has left to read will give the total number of pages.

That means that 120 pages is 40% of the book.

Make a proportion

120/40% = x/60%

72 = .4 x

x = 180 pages
5 0
3 years ago
Read 2 more answers
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