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Ksivusya [100]
3 years ago
14

there are 4 quarters for every one dollar and 10 dimes for every dollar. Without graphing, would the ratio of quarters to dollar

s appear to have a steeper line? Wxplain your reosoning
Mathematics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

no

Step-by-step explanation:

remember lines and line equations.

y = ax + b

a line has a slope indicating its angle relative to the basic coordinate axis and grid of x and y.

the slope is "a" in the generic equation, always the factor of x.

and it stands for the ratio y/x. it means how many units is y changing (and in what direction via its sign), when x changes a certain amount of units.

e.g. 3/4 means, when x changes 4 units to the positive (right) side, then y changes 3 units to the positive (up) side.

and also, when x changes 4 units to the negative (left) side, then y changes 3 units to the negative (down) side, as -/- is again +.

or -3/4 means, when x changes 4 units to the positive (right) side, then y changes 3 units to the negative (down) side, as -/+ is -.

and also, when x changes 4 units to the negative (left) side, then y changes 3 units to the positive (up) side, as +/- is again -.

so, we have here 2 ratios : 4/1 (quarters to dollars) and 10/1 (dimes to dollars).

remember what that means : y/x.

when x changes 1 unit to the right (x increases by 1), y changes 4 units up (y increases by 4).

and when x increases by 1 unit, y increases by 10 units.

what do you think is the steeper line ?

both are steep, as y increases much faster than x. but in the 10/1 ratio y increases much faster than in the 4/1 ratio. so, 10/1 is steeper than 4/1.

therefore, the answer is no. the ratio quarters to dollars does not represent a steeper line.

by the way, ratios like 4/1 or 10/1 are simply written 4 or 10.

so, when you see a line equation like y = 3x + 2,

you know the slope is 3 or actually 3/1.

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Answer:

The range in which at least 88.89% of the data will lie is (162,318).

Step-by-step explanation:

Given:

Average time spend online, \bar x = 4 hrs = 240 mins

Standard deviation, s = 26 mins

We have to find the range in which at least 88.89% of the data will lie by using Chebyshev's theorem :

Formula :

Lower range = \bar x-ks

Higher range = \bar x +ks

Now we have to find k values.

We know that the percentage of the data that lies within 'k' standard deviation is at least,1-1/k^2 and k > 1.

⇒ 88.89\% = 0.8889

⇒ 1-\frac{1}{k^2} = 0.8889

⇒ 1-0.8889=\frac{1}{k^2}

⇒ 0.1111=\frac{1}{k^2}

⇒ \frac{1}{0.1111} =k^2

⇒ \sqrt{\frac{1}{0.1111} } =k

⇒ 3=k

Plugging the value of k=3 in the formula above.

The range is \bar x-ks,\bar x+ks .

⇒ 240-3(26), 240+3(26)

⇒ 240-78,240+78

⇒ 162,318

So,

The range in which at least 88.89% of the data will lie is (162,318).

6 0
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