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abruzzese [7]
3 years ago
8

5C%20find%20%5C%3A%20the%20%5C%3A%20value%20%5C%3A%20of%20%5C%3A%20x" id="TexFormula1" title="4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x \\ find \: the \: value \: of \: x" alt="4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x \\ find \: the \: value \: of \: x" align="absmiddle" class="latex-formula">
fast please no wrong answer​
Mathematics
2 answers:
lbvjy [14]3 years ago
5 0

Answer:

4 {x}^{2}  - 2x + x = 5 {x}^{2}  + 2x \\ 4 {x}^{2}  - x = 5 {x}^{2}  + 2x \\ 4 {x}^{2}  - 5 {x}^{2}  = 2x + x \\  - 1 {x}^{2}  = 3x \\  - x = 3 \\ x =  - 3 \\ thank \: you

tatuchka [14]3 years ago
4 0

Answer:

\rm x = -3

Step-by-step explanation:

\rm 4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x

\rm 4x^{2}-x=5x^{2}+2x

\rm 4x^{2}-x-5x^{2}=2x

\rm -x^{2}-x=2x

\rm -x^{2}-x-2x=0

\rm -x^{2}-3x=0

\rm -x-3=0

\rm x = 3 \div (-1)

\bold{x = -3}

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2 + 3x²y - 1⁄2y + y - 1
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Answer:

3x²y+0.5y+1

Step-by-step explanation:

2+3x²y -0.5y+y -1

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4 0
2 years ago
Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

3 0
2 years ago
What is the area of a square with side lengths of 3/5 units?
umka2103 [35]

Answer:

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The units we'll use is  because units are the unt we're given, and it is squared because it is the area of a shape.

Your final answer is 0.36

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Step-by-step explanation:

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