Question

5C%20find%20%5C%3A%20the%20%5C%3A%20value%20%5C%3A%20of%20%5C%3A%20x" id="TexFormula1" title="4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x \\ find \: the \: value \: of \: x" alt="4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x \\ find \: the \: value \: of \: x" align="absmiddle" class="latex-formula">
fast please no wrong answer​

Answer 1

Answer:

$4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x \\ 4 {x}^{2} - x = 5 {x}^{2} + 2x \\ 4 {x}^{2} - 5 {x}^{2} = 2x + x \\ - 1 {x}^{2} = 3x \\ - x = 3 \\ x = - 3 \\ thank \: you$

Answer 2

Answer:

$\rm x = -3$

Step-by-step explanation:

$\rm 4 {x}^{2} - 2x + x = 5 {x}^{2} + 2x$

$\rm 4x^{2}-x=5x^{2}+2x$

$\rm 4x^{2}-x-5x^{2}=2x$

$\rm -x^{2}-x=2x$

$\rm -x^{2}-x-2x=0$

$\rm -x^{2}-3x=0$

$\rm -x-3=0$

$\rm x = 3 \div (-1)$

$\bold{x = -3}$