8600 because 6 is more near to zero than 8.So all the numbers after 6 become 00
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
14. (n-5)*4+7
15. No, this would not be neccesary because if I were to distribute 1/2 to both 4 and 6, I know that I would get half of those numbers which would give me 2x+3. I also know that if I distribute 1/3 to both 9 and 24, I would get 1/3 of each number which would be 3 and 8.
Answer:
y = (1/2)x + 1
Step-by-step explanation:
linear line equation is y = mx + b
Where m is the slope and b is the y-intercept when x is 0.
For m, m is change in y(delta y) over change in x(delta x).
We are given two points: (0,1) and (4,3).
m = (y2 - y1)/(x2 - x1) = (3-1)/(4-0) = 2/4 = 1/2
y = (1/2)x + b
Now plug in (0,1) into above equation to find b value.
1 = (1/2)0 + b => b = 1
Final equation is y = (1/2)x + 1
