First, we need to put the numbers in order...
58,60,69,71,78,78,85,85,86,87,88,91,93,95,95,95,96,98,100,100
and since there is an even number of numbers (20), we need to find the 2 middle numbers and divide them by 2 to find the median (Q2)
Q2 (the median) = (87 + 88) / 2 = 175/2 = 87.5
now we take all the numbers below 87.5...and find the median (middle number) and that number will be Q1...there is 2 middle numbers...so we add them and divide by 2
Q1 = (78 + 78) / 2 = 156/2 = 78
now we take all the numbers after 87.5....and find the median...there will be 2 numbers, so we add them and divide by 2..that wil be Q3
Q3 = (95 + 95) / 2 = 190/2 = 95
So in summary :
Q1 = 78 <==
Q2 = 87.5
Q3 = 95 <==
The interquartile range (IQR) is found by subtracting Q1 from Q3.
IQR = 95 - 78 = 17 <==
Answer:
Step-by-step explanation:
2 hours × 60 km/hour = 120 km
390-120 = 270 km remaining
270 km/(3 hours) = 90 km/hour
5x6 = 30 and 9x4 = 36 so 30+36= 66
Answer: a is the # of elements in A but NOT B, that is A ONLY
b is the # of elements in B but NOT A, that is B only
N is the # of elements in the INTERSECTION of A and B
a + N = 99
b + N = 25
a + b + N = 123
Subtracting the first two equations: a - b = 74
Subtracting the last two equations: -a = -98
a = 98
So then a - b = 74 and a = 98
98 - b = 74
-b = -24
b = 24
a = 98, b = 24 and a + b + N = 123
98 + 24 + N = 123
122 + N = 123
N = 1
98 are in A only
24 are in B only , which is the answer to the question
1 is in both A and B
Step-by-step explanation:
Answer:
a geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-one number called the common ratio. hope this helped :)
Step-by-step explanation:
