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3 years ago

What is the range of the function shown on the graph above? The graph is in the photo

Mathematics

1 answer:

Alex777 [14]3 years ago

6 0

The answer is OA. 6 & it; y & it; 9

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Get 23 pts for doing 23 and 24 Not too easy to see, sorry. But it is readable..

Mice21 [21]

Answer:

23:480,000

Step-by-step explanation:

5 0

3 years ago

There are two plates of kit kats on a table.One plate has 3 whole kit kats on it. On the other plate, each kit kat bar was spilt

kvv77 [185]

Plate 1 : 3 whole kit-kats
plate 2 : each kit-kat split into 2 equal pieces....there are 8 pieces...8/2 = 4 kit-kats

plate 2 has more kit-kats

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4 years ago

Find the area of the semicircle.

Wewaii [24]

Answer:

6.28

Step-by-step explanation:

6 0

4 years ago

HELP PLS ITS ALGEBRA 1

Georgia [21]

Answer:

$- \frac{2}{6}$

Step-by-step explanation:

Use distributive property to simplify both sides.

$\frac{1}{6} (1 - 6x) = - \frac{1}{3} ( 6x + \frac{1}{2} )$

Use the Golden Rule of Algebra: (What we do to one side, we must do to the other).

$\frac{1}{6 } - x = - 2x - \frac{1}{6}$

$\frac{1}{6} = - x - \frac{1}{6}$

$\frac{2}{6 } = - x$

$x = - \frac{2}{6}$

5 0

3 years ago

Read 2 more answers

A 30° 60° 90° triangle is shown below. Find the length of the side labeled y.

bulgar [2K]

Answer:

Part 1) $y=3\ units$

Part 2) The length of the hypotenuse is 6 units

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

$sin(60^o)=\frac{y}{2\sqrt{3}}$ ----> by SOH (opposite side divided by the hypotenuse)

solve for y

$y=sin(60^o)2\sqrt{3}$

Remember that

$sin(60^o)=\frac{\sqrt{3}}{2}$

substitute

$y=(\frac{\sqrt{3}}{2})2\sqrt{3}$

$y=3\ units$

Part 2)

Let

h ----> the length of the hypotenuse

we know that

In the right triangle of the figure

$sin(45^o)=\frac{3\sqrt{2}}{h}$ ----> by SOH (opposite side divided by the hypotenuse)

$h=\frac{3\sqrt{2}}{sin(45^o)}$

Remember that

$sin(45^o)=\frac{\sqrt{2}}{2}$

substitute

$h=3\sqrt{2}:\frac{\sqrt{2}}{2}$

$h=6\ units$

7 0

3 years ago