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Pavel [41]
3 years ago
7

The dimensions of a trapezoid are shown below.

Mathematics
1 answer:
Trava [24]3 years ago
7 0

Answer:

26cxm

Step-by-step explanation:

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A sequence is defined by the recursive function f(n + 1) =
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f(1)=9

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Given \ f(n+1)=f(n)\\f(3)=f(2)\\f(2)=f(1)\\f(1)=f(2)=f(3)\\f(1)=f(3)\\f(1)=9

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What is 2/3 of 1/5th?
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Find the nth maclaurin polynomial for the function. f(x) = 5x − 5 x + 1 , n = 4 p4(x)
zysi [14]
Assuming the function is f(x)=\dfrac{5x-5}{x+1}, and not 5x-5x+1=1 which would be its own Maclaurin polynomial right away.

\dfrac{5x-5}{x+1}=\dfrac{5(x-1)}{x+1}=\dfrac{5(x+1-2)}{x+1}=5-\dfrac{10}{1+x}

Recall the geometric power series,

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

where |x|. Replace x\mapsto-x and we have

\displaystyle\sum_{n=0}^\infty (-x)^n=\frac1{1+x}

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We want the 4th degree polynomial, so

p_4(x)=-5+10x-10x^2+10x^3-10x^4
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3 years ago
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