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Allisa [31]
3 years ago
7

yo can someone please help me out. school is rlly stressful and i just need help. the question is “find the perimeter and area o

f each figure. use 3.14 for pi when needed.” the work is on composite figures. tysm <3

Mathematics
1 answer:
Bess [88]3 years ago
6 0
These will be the answers

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Can someone please help
Pie
Correct answer is D

Would appreciate brainliest answer :)
3 0
3 years ago
3 2/3 divided by 2 2/3
Goshia [24]

Answer:

1 3/8

Step-by-step explanation:

3 2/3 = 11/3

2 2/3 = 8/3

11/3 / 8/3 = 11/3*3/8 = 11/8 = 1 3/8

5 0
3 years ago
Read 2 more answers
80 is 25% of what number
alex41 [277]
320 is the answer just add 80 four times

3 0
4 years ago
Read 2 more answers
In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles,
bonufazy [111]

Answer:

Phillipa rode the most in May and rode the least in March.

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

Step-by-step explanation:

Given:

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.

To find: the month when she rode the most and the month when she rode the least

Solution:

Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles

Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = \frac{132}{2}=66 miles

Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles

So, she rode the most in May and rode the least in March

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

8 0
3 years ago
Solve: (1/8)^-3a = 512^3a
svlad2 [7]
A= 1/3288 I think it’s the answer
8 0
4 years ago
Read 2 more answers
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