We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is 
. The graph of the function does not show a phase shift. We are asked to write the equation of our function.
We know that general form a cosine function is 
, where,
A = Amplitude,
= Period,
c = Horizontal shift,
d = Vertical shift.
The equation of parent cosine function is 
. Since function is reflected about x-axis, so our function will be 
.
Let us find the value of b.
Upon substituting our given values in general cosine function, we will get:
Therefore, our required function would be .
Answer:
-17.67 +3.43i
Step-by-step explanation:
Carry out the indicated math:
18 cis 169° = (18·cos(169°) +i·18·sin(169°)) = (18·(-0.9816) +i·18·0.1908)
= -17.67 +i·3.43
The answer is B. 16.1 square meters
The region has triangular shape. To calculate the area of the triangle when three sides are known, we will use the Heron's formula:
A = √s(s-a)(s-b)(s-c)
where:
A - the area of the triangle
a, b, and c - the sides of the triangle
s - half of the triangle's perimeter: s = (a+b+c)/2
It is given:
a = 13 m
b = 5 m
c = 9 m
First, calculate s:
s = (a+b+c)/2 = (13+5+9)/2 = 13.5
Now, it is easy to calculate the area:
A = <span>√s(s-a)(s-b)(s-c) = </span>√13.5(13.5-13)(13.5-5)(13.5-9) = √13.5×0.5×8.5×4.5 = √258.19 = 16.07 ≈ 16.1
Answer:
is a function
Step-by-step explanation:
The relation is a polynomial. Every polynomial is a function, so the relation is a function. (Each value of x produces a single corresponding value of y.)
<span>The issue that results from the combination of limited resources and unlimited wants? is: Scarcity </span>
