This is the concept of trigonometry, we are required to find the vertical asymptote of the function given by;
y=2tan x
For any y=tan x, vertical asymptotes occur at the point x=π/2+nπ, where is an integer given by n=0,1,2,3...
Therefore we can generate the vertical asymptotes as follows;
When x=0
y=π/2
when x=1
y=π/2+π
y=3/2π
when x=2
y=π/2+2π
y=5/2π
Therefore at the interval [0,2π]
The vertical asymptotes are:
π/2, 3/2π, 5/2π
It's 14+0.05
It's that easy
Answer:
sqrt(1/2x+6) = h^-1 (x)
Step-by-step explanation:
To find the inverse, we exchange x and y and then solve for y
y = 2x^2 -12
Exchange x and y
x = 2y^2 -12
Solve of y
Add 12 to each side
x+12 = 2y^2
Divide by 2
(x+12) /2 = 2y^2/2
(x+12)/2 =y^2
1/2 x+6 = y^2
Take the square root of each side
sqrt(1/2x+6) = sqrt(y^2)
sqrt(1/2x+6) = y
This is the inverse