DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
1.) Height of a coffee cup
2.) Kitchen tiles
3.) Height of a microwave
Answer:
Step-by-step explanation:
Use “D = R x 2”, in which "D" equals diameter and "R" equals radius, to solve for the diameter using the numbers you got earlier. Then use “C = pi x D”, in which "C" equals circumference, to solve for the circumference.
Answer:
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