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arsen [322]
3 years ago
15

In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at

the end of 2 hours if the count was initially 5, 06,000.
follow for follow ​

Mathematics
1 answer:
DedPeter [7]3 years ago
5 0

Answer:

5,31,616 bacteria

Step-by-step explanation:

Solution:

Here, Principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time (n) = 2 hours

After 2 hours, number of bacteria,

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+100R)n

= 506000\left(1+\frac{2.5}{100}\right)^2506000(1+1002.5)2

= 506000\left(1+\frac{25}{1000}\right)^2506000(1+100025)2

= 506000\left(1+\frac{1}{40}\right)^2506000(1+401)2

= 506000\left(\frac{41}{40}\right)^2506000(4041)2

= 506000\times\frac{41}{40}\times\frac{41}{40}506000×4041×4041

= 5,31,616.25

Hence, number of bacteria after two hours are 531616 (approx.).

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Answer:

7sqrt(15) - 5sqrt(6)

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Step-by-step explanation:

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-----------------------

3 sqrt(5) *sqrt(3)

7 -sqrt(10)

-----------------------

3 sqrt(15)

Multiply the top and bottom by sqrt(15)/ sqrt(15)

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----------------------- * ------------

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sqrt(ab) =sqrt(a) sqrt(b)

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7sqrt(15) - 5sqrt(6)

------------------------------

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3 years ago
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Answer:

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Step-by-step explanation:

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mars1129 [50]
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Hope this helps!
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12 is the answer hope it help
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Is the difference of two positive rational number always positive explain
Dominik [7]
No . . . while the difference represents the absolute magnitude between two numbers . . . for example . . .

<em>The difference between 5 and 2 is . . . 3</em>
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