Question

Prove algebraically that the recurring decimal 0.72 =8/11

Answer 1

Answer:

see explanation

Step-by-step explanation:

We require 2 equations with the recurring decimal placed after the decimal point.

let x = 0.7272.... (1) ← multiply both sides by 100

100x = 72.7272... (2)

Subtract (1) from (2) thus eliminating the recurring decimal

99x = 72 ( divide both sides by 99 )

x = $\frac{72}{99}$ = $\frac{8}{11}$

Answer 2

Answer:

true

Step-by-step explanation:

because 8÷11=0.72

72÷10

=8÷11

=0.72