Prove algebraically that the recurring decimal 0.72 =8/11
2 answers:
Answer:
see explanation
Step-by-step explanation:
We require 2 equations with the recurring decimal placed after the decimal point.
let x = 0.7272.... (1) ← multiply both sides by 100
100x = 72.7272... (2)
Subtract (1) from (2) thus eliminating the recurring decimal
99x = 72 ( divide both sides by 99 )
x = =
You might be interested in
Integers are numbers without decimals
The integers could you have multiplied are 9 and 2
Let the numbers be x and y
So, we have:
Increase x by 1 and reduce y by 1.
So, we have
Open brackets
Subtract xy from both sides
Collect like terms
Rewrite as:
The above means that, the difference between the integers is 7.
There are several integers that fit the above <em>description</em>;
One possibility is: 9 and 2
Read more about products at: