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pentagon [3]
2 years ago
14

PLS HELP ME PLSS!!!!! ; _ ;​

Mathematics
1 answer:
slava [35]2 years ago
8 0

Answer:

a) P(not red) = 37/49

b) P(purple) = 17/49

Step-by-step explanation:

Prob. of not red = (20+17) / (12+20+17) = 37/49

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PLEASE HELP ME????!!!?
Eduardwww [97]

Step-by-step explanation:

what is the question ?

check everything that applies to the angles 1 and 2 ?

in that case :

two angles are adjacent angles, when they share a vertex and side.

so, yes, adjacent angles is true

vertical angles are angles that are opposite of each other when two lines cross.

so, no, vertical angles is false.

two angles are complementary, when they are adjacent and have combined 90°.

so, yes, complementary angles is true.

2 angles are supplementary, when they are adjacent and have combined 180°.

so, no, supplementary angles is false.

a linear pair of angles is basically the same as supplementary angles.

they are formed when two lines intersect each other (at a single point). The angles at the intersection point are linear if they are adjacent to each other, and their sum is always equal to 180°.

so, no, linear pair is false.

8 0
2 years ago
PLEASE HELPPPP IM STRUGGLING FR
MAVERICK [17]

Answer:

I think it's answer is B, A rotation around point 0 and then a reflection

3 0
3 years ago
Read 2 more answers
Which measure is always the 50th percentile?<br> mean<br> median<br> upper quartile
Ber [7]

Answer:

median

Step-by-step explanation:

the median is literally the middle number--half the numbers are higher, half the numbers are lower.

4 0
3 years ago
Line I is parallel to line m. If the
Ira Lisetskai [31]

Answer:

75

Step-by-step explanation:

alternate interior angles are always equal, so that means 6 = 4 = 75.

3 0
3 years ago
If we approximate the function y=sin(x) with a0+a1 x a2 x^2 +a3 x^3, what is a0,a2,a2,a3?
Rashid [163]

The coefficients a_0,a_1,a_2,a_3 could be chosen to be the coefficients in the Maclaurin series of \sin(x).

We have

y = \sin(x) \approx a_0 + a_1 x + a_2 x^2 + a_3 x^3 \\\\ \implies y(0) = 0 = a_0

y' = \cos(x) \approx a_1 + 2a_2 x + 3a_3 x^2 \\\\ \implies y'(0) = 1 = a_1

y'' = -\sin(x) \approx 2a_2 + 6a_3 x \\\\ \implies y''(0) = 0 = 2a_2

y''' = -\cos(x) \approx 6a_3 \\\\ \implies y'''(0) = -1 = 6a_3

It follows that a_0=0, a_1=1, a_2=0, and a_3 = -\frac16.

7 0
2 years ago
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