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2 years ago

15

Mr. Cruz bought 9 3/5 kg of meat. He used 2 3/5 kg for adobo, 4 3/5 kg for menudo and the rest for afritada. How many kilograms

of meat did he use for afritada?

1 answer:

Ray Of Light [21]2 years ago

5 0

Answer:

3 3/5

Step-by-step explanation:

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If a ladder is 5.5 m long and it is placed 3 m from the wall, solve and show the work when you use the Pythagorean Theorem to fi

natali 33 [55]

Answer:

4.609 meters

Step-by-step explanation:

The hypotenuse is the ladder because it is the slanted side. 3m is one of the other side lengths

A^2 + B^2 = C^2

3^2 + B^2 = 5.5^2

9 + B^2 = 30.25

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2 years ago

Write the statement in if-then form.

Vilka [71]

I believe the answer is A because its the only one that makes the most sense.

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2 years ago

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In congruent figures, corresponding angles have equal measures. true or false?

algol [13]

This is true

Think of two houses. If we say "the houses are identical" then the corresponding pieces must be the same (eg: the doors must be the same type out of the same material). In this analogy, the houses are the triangles, which are the overall structures. The doors are the angles since they are pieces of the overall structures. This is what CPCTC is saying

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3 years ago

You have a dance class every three days. Today is Monday, and you have dance class. In how many more days will you have dance cl

Dafna11 [192]

7 days in a week, 3 days a rotation.

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3 years ago

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larisa86 [58]

A. Every month Population will increase by a factor of 0.84%.

B. Every 3 months Population will increase by a factor of 2.5%.

C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.

<u>Step-by-step explanation:</u>

Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as $x + \frac{x}{100}\times10$ which is equivalent to $\frac{11x}{10}$ .

<u>A.</u>

For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like $\frac{10}{12} = 0.84$ . ∴ Every month Population will increase by a factor of 0.84%.

<u>B.</u>

In every 3 months: We have , 12 months in a year , in order to check for every 3 months $\frac{12}{3} = 4$ and Now, Population increase in every 3 months is $\frac{10}{4} = 2.5$ . ∴ Every 3 months Population will increase by a factor of 2.5%.

<u>C.</u>

In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.

So , increase in population in every 20 months is 10% + 6.72% = 16.72%.

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3 years ago