Positive cosine is first or fourth quadrant. So we don't know the sign of the sine or the tangent.
Everybody's favorite right triangle is 3/4/5 and here we have

So if

then

and

Solve either equation for either variable. Since the second one has y on its own, the easiest choice is to solve that for y.
-5x + y = 13 ⇒ y = 5x + 13
Now substitute this into the other equation to eliminate y and rewrite it entirely in terms of x :
-3x + 3y = 3 ⇒ -3x + 3 (5x + 13) = 3
Simplify and solve for x :
-3x + 15x + 39 = 3
12x = -36
x = -3
Substitute this into either original equation to solve for y. Plugging x = -3 into the first equation would give
-3 (-3) + 3y = 3
9 + 3y = 3
3y = -6
y = -2
So the solution to the system of equations is (x, y) = (-3, -2).
I got y=2/3x + 10 , i hope that’s right!
Answer:
thx i see there everywhere
Step-by-step explanation:
select the one that says "no, the estimate should be higher."