2 years ago

Help please !!!!!!!! !!!!!!!!!!!!

Mathematics

1 answer:

lina2011 [118]2 years ago

3 0

The answer would be 4/9

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PLEASE HELP! 20 POINTS + BRANLIEST WILL BE GIVEN

SOVA2 [1]

Answer:

The answer is 22.5 miles

Step-by-step excplanation:

5 0

2 years ago

Find the slope of the like y = 1/8x -1 anser choices -8/1 1/8 1 -1

otez555 [7]

Answer:

The equation is not linear. So the slope does not exist. Not linear.

Maybe you wrote the equation wrong? If so, let me know and I'll tell you what the answer is.

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3 years ago

I NEED THE ANSWER ITS DUE SOON !!! Points will be rewarded

DENIUS [597]

Answer:

Jaden added instead of subtracting 23 and 5

Step-by-step explanation:

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2 years ago

Indicate the equation of the given line in standard form, in the equation box below.

Illusion [34]

Perpendicular lines have slopes that are negative reciprocals of each other, so the equation of the line in point-slope form is:

$y-4=-\frac{5}{2}(x+3)$

Rewriting this in standard form,

$2y-8=-5(x+3) \\ \\ 2y-8=-5x-15 \\ \\ \boxed{5x+2y=-7}$

6 0

2 years ago

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

hoa [83]

Answer:

$\frac{dI}{dt}=-0.00016 A/s$

Step-by-step explanation:

We are given that

By ohm's law

$V=IR$

R=389 ohm

I=0.03 A

$\frac{dV}{dt}=-0.06V/s$

$\frac{dR}{dt}=0.07ohm/s$

We have to find rate of change of current I means $\frac{dI}{dt}$

Differentiate the equation w.r.t t

$\frac{dV}{dt}=\frac{dI}{dt}R+I\frac{dR}{dt}$

Substitute the values then we get

$-0.06=\frac{dI}{dt}\times 389+0.03\times 0.07$

$-0.06=389\frac{dI}{dt}+0.0021$

$-0.06-0.0021=389\frac{dI}{dt}$

$-0.0621=389\frac{dI}{dt}$

$\frac{dI}{dt}=\frac{-0.0621}{389}=-0.000160 A/s$

Hence, the current I is changing at the rate=-0.00016A/s

4 0

3 years ago