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inn [45]
3 years ago
10

can someone at least help me with this math problem that i'm getting frustrated with. 2y^3-4x^2-4-1+3x^2-3y^3-y^3

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

See explanation for answer.

Step-by-step explanation:

Original equation: 2y^3-4x^2-4-1+3x^2-3y^3-y^3

= 2y^3 + −4x^2+ −4+ −1 + 3x^2+ −3y^3 + −y^3

= 2y^3 + −4x^2+ −4 + −1 + 3x^2+ −3y^3 + −y^3

= (2y^3 + −3y^3+ − y^3)+(−4x^2 + 3x^2)+(−4+ −1)

= −2y^3+ −x^2 + −5

Answer: = −2y^3 − x^2 − 5

I'm sorry if this is incorrect. I tried my best.

I hope I helped!

Have a  lovely day!

expeople1 [14]3 years ago
6 0

Answer:

ans= -2y^3-x^2-5

Step-by-step explanation:

(i) write the question nicely again.

(ii) collect the like and unlike terms.

(iii)solve (add and minus ) according to their like and unlike terms.

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