Answer:
See explanation for answer.
Step-by-step explanation:
Original equation: 2y^3-4x^2-4-1+3x^2-3y^3-y^3
= 2y^3 + −4x^2+ −4+ −1 + 3x^2+ −3y^3 + −y^3
= 2y^3 + −4x^2+ −4 + −1 + 3x^2+ −3y^3 + −y^3
= (2y^3 + −3y^3+ − y^3)+(−4x^2 + 3x^2)+(−4+ −1)
= −2y^3+ −x^2 + −5
Answer: = −2y^3 − x^2 − 5
I'm sorry if this is incorrect. I tried my best.
I hope I helped!
Have a lovely day!
ans= -2y^3-x^2-5
(i) write the question nicely again.
(ii) collect the like and unlike terms.
(iii)solve (add and minus ) according to their like and unlike terms.
−2x2+16x−8
-2*(6y-3x+9)
no they are not because 11, 14 is the only one that has a vertices
