one way is to solve for the invers of the first function
remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)
A.
f(x)=x/2+8
y=x/2+8
x=y/2+8
x-8=y/2
2x-16=y
f⁻¹(x)=2x-16
nope, not A
B.
f(x)=3x³+16
y=3x³+16
x=3y³+16
x-16=3y³
(x-16)/3=y³
∛((x-16)/3)=y
f⁻¹(x)=∛((x-16)/3)
nope, not the same
not B
C.
f(x)=18/x-9
y=18/x-9
x=18/y-9
x+9=18/y
y(x+9)=18
y=18/(x+9)
f⁻¹(x)=18/(x+9)
correct, the answer is C
answer is C
X/(9+11)=4 bc x is the “number” and “9, and 11” means add them together. Put the in parenthesis
Answer:
70% of the people at the fair are students
165 people are on the ride
Step-by-step explanation:
In order to find a percentage, take the fraction given, 385/550, and divide the numerator, 385, and divide it by the denominator, 550. Once completing this, we get 0.7
Next, we multiply the result by 100, and get 70, thus, 385 is 70% of 550.
To find how many people 30% of 550 is, we take the percentage and put it in a fraction with the denominator being 100(changes with size of fraction like a decimal, 300 would be over a denominator of 1000)
With 30/100, we then multiply by 550 with the equation looking like this:
30/100*550/1
Once we finish multiplying(typically using a calculator, although you can do it manually) we get 165, the value of how many people are on rides out of the total 550.
An example scenario is:
Anthony goes to the gym for <em>20</em> minutes on Monday. Every day he <em>multiplies</em> his gym time by <em>2</em>.
On the fifth day, he will spend spend 320 minutes in the gym.
The formula used to determine the 5th term is,
a5 = 20 x 2^(r -1)
where r is the common ratio equal to 2.
12 can only go into 30 about 25 whole times.
