NEED FULL EXPLANATION!!

2 answers:

4 0

Answer:

Step-by-step explanation:

This is a typical probability question where there is a large number of possible outcomes to be considered.

That suggests an approach where we look at the probability of it not occurring.

For that to happen, we have to have 5 coins all landing heads up. The probability of that happening is (1/2)5=1/32.

From this, we can deduce the probability of that not happening (i.e. there being at least one tail) is 1−1/32=31/32.

3 0

<h2>A COIN IS TOSSED 5 TIMES.</h2><h2>A COIN IS TOSSED 5 TIMES.FIND THE PROBABILITY OF GETTING AT LEAST 1 TAILED</h2>

So we can see that the probability of all tails in 5 throws is 132 . We can say that the probability of getting at least one head =1− probability of one head. So the required probability by putting value is 1−132 . Hence the correct option is (d) 3132 .

hope it help

#carry on learning

correct me if I'm wrong

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andre [41]

Answer:

Step-by-step explanation:

since -4 *-2 = 8 and -8+8=0

0*-2=0

0+5=5

7 0