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Tomtit [17]
3 years ago
9

Find the first five terms of each arithmetetic sequence describe a1 = -12 d = 5

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

- 12, - 7, - 2, 3, 8

Step-by-step explanation:

The general terms of an arithmetic sequence are

a, a + d, a + 2d + ....... + a + (n - 1 )d

To obtain consecutive terms in the sequence add d = 5 to the previous term

a_{1} = - 12

a_{2} = - 12 + 5 = - 7

a_{3} = - 7 + 5 = - 2

a_{4} = - 2 + 5 = 3

a_{5} = 3 + 5 = 8

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Let f(x) = 4x - 3 and h(x) = -5x + 7 . F(-3) + h(2)
zheka24 [161]
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5 0
4 years ago
Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
Read 2 more answers
Which is equivalent to square root 10st x square root 15tu
aivan3 [116]

\sqrt{10st}\cdot\sqrt{15tu}=\sqrt{10st\cdot15tu}=\sqrt{150st^{2}u}=\sqrt{25\cdot6\cdot st^{2}u} =   \\\\= \sqrt{5^{2} \cdot t^{2}\cdot6 \cdot su}=5t\sqrt{6su}

4 0
3 years ago
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