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olga55 [171]
3 years ago
15

A bird is flying horizontally at 9.12 m/s. Suddenly, the bird drops a small stone that it was carrying with its

Physics
1 answer:
Ivahew [28]3 years ago
6 0

25.08m

Explanation:

velocity=9.12m/s

time=2.75s

R(horizontal range)=velocity*time

=9.12*2.75

=25.08m

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Sabe-se que um alqueire paulista equivale a 24200 metros quadrados. Uma chácara retangular tem um alqueire e mede 100m de frente
sattari [20]

Answer:

b = 242 m

Explanation:

A = 24200 m²

a = 100 m

b = ?

A seguinte fórmula é aplicada

A = a*b

⇒  b = A / a

⇒  b = (24200 m²) / (100 m)

⇒  b = 242 m

5 0
3 years ago
In the fabrication of an electrical extension cord, the manufacturer wants to reduce the overall resistance of the wires in the
Bezzdna [24]

Answer:

Option B is correct.

Explanation:

The resistance of a material or wire is represented by the formula below.

R=(ρL)/A

where

  • R is resistance of wire
  • ρ is the resistivity of the material
  • A is the cross sectional area of wire
  • L is length of wire

Resistance increases with increase in length and resistivity which means options C and D are wrong.

A=(πd^{2})/4

An increase in diameter will result in a proportional increase in area

From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct

Have a great day

5 0
3 years ago
Can someone help meeeeee... show how to solve it plzzzzzzzz
liubo4ka [24]
<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have a gravitation force F_{1}=16units, given by the formula written at the beginning. Let’s rename the distance r as d:

F_{1}=G\frac{m_{1}m_{2}}{d^2}     (1)

And we are asked to find the gravitation force F_{2} with a given distance of \frac{d}{2}:

F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}      

F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}     (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate G m_{1}m_{2} in both equations:

From (1):

Gm_{1}m_{2}=F_{1}{d}^{2}     (3)

From (2):

Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}     (4)

If (3)=(4):

F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}     (5)

Now we have to find F_{2}:

F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}      

F_{2}=4F_{1}     (6)

If F_{1}=16 units:

F_{2}=(4)(16 units)        

F_{2}=64 units>>>>This is the new force of attraction     

3 0
3 years ago
Question 7 of 20
slamgirl [31]

Answer:

high number of coils in the wire

5 0
3 years ago
An electron and a proton are initially very far apart (effectively an infinite distance apart). They are then brought together t
Lina20 [59]

Answer:

dU=-4.36*10^{-18}J

Explanation:

From the question we are told that:

Average distance d_{avg} =5.29*10^{-11}m

Generally the equation for change in electric potential energy is mathematically given by

dU=u_f-U_1

Where

U_1=0 Because of initial lengthy distance apart

And

U_f=\frac{kq_eq_p}{d}

U_f=\frac{9*10^9*1.6*10^{-19}*-1.6*10^{-19}}{5.29*10^{-11}}

U_f=-4.36*10^{-18}J

Therefore

dU=u_f-U_1

dU=-4.36*10^{-18}J-0

dU=-4.36*10^{-18}J

3 0
3 years ago
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