If an object were released in space far away from planted or stars and given an initial momentum, describe what would happen to
2 answers:
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Answer:
The answer is .
Explanation:
From the law of gravity,
considering F as a conservative force, ,
the general expression for gravitational potential energy is
,
where G is the gravitational constant, M and m are the mass of the attracting bodies, and r is the distance between their centers. The negative sign is because the force approaches zero for large distances, and we choose the zero of gravitational potential energy at an infinite distance away.
However, as the mass of the Sun is much greater than the mass of the rock, the gravitational acceleration is defined as
,
(the negative sign indicates that the force is an attractive force), and the potential energy between the rock and the Sun is
,
which is actually the total energy of the system, because the rock materializes stationary at this point (there is no radial kinetic energy).
When the rock hits the surface of the Sun, almost all potential energy is converted to kinetic energy, but not all because the Sun is not a puntual mass. So the potential energy converted to kinetic energy is
,
then, the kinetik energy when the rock hits the surface is
,
so
where g is the gravitational acceleration generated by the Sun at R,
.
Answer:
68 m
Explanation:
Given that the horizontal velocity of the birdman = 17 m/s and
the height, h= 78 m.
The gravitational force is acting in the downward direction, so it will not change the horizontal speed.
The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.
Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, m/s.
In the vertical direction, u = 0,
The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e
s= 78 m
Let t be the time taken to cover a distance of 78 m.
Now, applying the equation of motion in the vertical direction,
where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.
Here, , so
seconds.
Hence, the time taken to reach the ground is 4 seconds.
As the horizontal speed, m/s, is constant throughout the journey, so
the horizontal distance covered by turd
m.
So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly above the start of the field.
Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.