I believe D is ur answer..................
Answer:
her acceleration is 1 m/sec
Explanation:
The following information is given in the question
The initial velocity is 5 m/s
After 10 seconds, she would be moved at 15 m/s
We need to find the acceleration
As we know that
Acceleration = Change in speed ÷ time
Acceleration = (15 - 5) ÷ (10)
= 1 m/sec
Hence, her acceleration is 1 m/sec
The same would be considered
This item is solved through the concept of the conservation of momentum which states that the momentum before and after collision should be equal.
momentum = mass x velocity
(1,600 kg)(16 m/s) + (1.0x10^3 kg)(10 m/s) = (1600 + 1000 kg)(x)
The value of x is 13.69 m/s. Thus, their final speed is approximately letter D. 14 m/s.
Explanation:
the pressure is given by P=hpg
where h is height,p is density, g is 10m/s²
thus P= 0.05m•13.6x10³•10
P=6.8x10³ Hgmm
Answer:
6.4 J
Explanation:
m = mass of the bullet = 10 g = 0.010 kg
v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s
v' = final velocity of the bullet after collision = 1 km/s = 1000 m/s
M = mass of the block = 5 kg
V = initial velocity of block before collision = 0 m/s
V' = final velocity of the block after collision = ?
Using conservation of momentum
mv + MV = mv' + MV'
(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'
V' = 1.6 m/s
Kinetic energy of the block after the collision is given as
KE = (0.5) M V'²
KE = (0.5) (5) (1.6)²
KE = 6.4 J