Answer:correct answers are:
A.m<JPX=90°
B.XY & JK form right angles
E. JP=KP
F.XY⊥JK
Step-by-step explanation:
hope this helps
First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
I hope this helps you
y=-2x
x+3.(-2x)=15
x-6x=15
-5x=15
x=-3
y=-2.-3=6
27/4
4*6=24
27-24=3
remainder is 3
Answer:
17.5 hours
Step-by-step explanation:
5x-5 over 4 days and the plan to travel 4.5 hours each day. WE have to find how many hours will they drive each day. Now, to find the total time pu x to 4.5 in the above expression. 5(4.5)-5
= 22 * 5-5 = 17. 5 hours over the four days of traveling
