The Laplace transform of the given initial-value problem
is mathematically given as
<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>
Generally, the equation for the problem is mathematically given as
![&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}](https://tex.z-dn.net/?f=%26%5Ctext%20%7B%20Sol%3A-%20%7D%20%5Cquad%20y%5E%7B%5Cprime%7D%2Bs%20y%3De%5E%7B4%20t%7D%2C%20y%280%29%3D2%20%5C%5C%5C%5C%26%5Ctext%20%7B%20Taking%20Laplace%20transform%20of%20%281%29%20%7D%20%5C%5C%5C%5C%26%5Cquad%20L%5Cleft%5By%5E%7B%5Cprime%7D%2B5%20y%5Cright%5D%3D%5Cleft%5B%5Cleft%5Be%5E%7B4%20t%7D%5Cright%5D%5Cright.%20%5C%5C%5C%5C%26%5CRightarrow%20%5Cquad%20L%5Cleft%5By%5E%7B%5Cprime%7D%5Cright%5D%2B5%20L%5By%5D%3D%5Cfrac%7B1%7D%7Bs-4%7D%20%5C%5C%5C%5C%26%5CRightarrow%20%5Cquad%20s%20y%28s%29-y%280%29%2B5%20y%28s%29%3D%5Cfrac%7B1%7D%7Bs-4%7D%20%5C%5C%5C%5C%26%5CRightarrow%20%5Cquad%28s%2B5%29%20y%28s%29%3D%5Cfrac%7B1%7D%7Bs-4%7D%2B2%20%5C%5C%5C%5C%26%5CRightarrow%20%5Cquad%20y%28s%29%3D%5Cfrac%7B1%7D%7Bs%2B5%7D%5Cleft%5B%5Cfrac%7B1%7D%7Bs-4%7D%2B2%5Cright%5D%3D%5Cfrac%7B2%20s-7%7D%7B%28s%2B5%29%28s-4%29%7D%5Cend%7Baligned%7D)
In conclusion, Taking inverse Laplace tranoform
![L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\](https://tex.z-dn.net/?f=L%5E%7B-1%7D%5By%28s%29%5D%3D%5Cfrac%7B1%7D%7B9%7D%20L%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B1%7D%7Bs-4%7D%5Cright%5D%2B%5Cfrac%7B17%7D%7B9%7D%20L%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B1%7D%7Bs%2B5%7D%5Cright%5D%24%20%5C%5C%5C%5C)
Read more about Laplace tranoform
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The domain and range of a function is the set of input and output values, the function can take.
- <em>The domain is [0,6]</em>
- <em>The range is [0,90]</em>
<em />
From the question, we have:
<u>The domain</u>
He cannot mow more than 6 yards a day.
This means that the domain is: 0 to 6
<em>This is properly represented as: [0,6]</em>
<u></u>
<u>The range</u>
When he mows 0 yards, his earnings is:
When he mows 6 yards, his earnings is:
This means that the range is: 0 to 90
<em>This is properly represented as: [0,90]</em>
Read more about domain and range at:
brainly.com/question/4767962
<h3>
Answer: No, they are not similar.</h3>
Technically, we don't have enough info so it could go either way.
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Explanation:
We can see that the sides are proportional to each other, but we don't know anything about the angles. We need to know if the angles are the same. If they are, then the hexagons are similar. If the angles are different, then the figures are not similar.
Right now we simply don't have enough info. So they could be similar, or they may not be. The best answer (in my opinion) is "not enough info". However, your teacher likely wants you to pick one side or the other. We can't pick "similar" so it's best to go with "not similar" until more info comes along the way.
Answer:
A. 3 bags of oranges, 4 bags of apples
Step-by-step explanation:
If O is number of bags of oranges and A is number of bags of apples:
O + A = 7
5O + 3A = 27
We can solve this system of equations with either substitution or elimination. I like to use substitution, but you can use whichever you prefer.
O = 7 − A
5 (7 − A) + 3A = 27
35 − 5A + 3A = 27
35 − 2A = 27
8 = 2A
A = 4
O = 7 − A
O = 3
Teresa bought 3 bags of oranges and 4 bags of apples.
The answer to your question is 67
