Area of the shaded sector = (120/360) * pi * 10^2
= 104.72 square units
Area of the other sector = 2 * 104.72 = 209.44 sq units
Answer:
1) f(g(2)) = 24
2) f(g(-1)) = -4
Step-by-step explanation:
1) GIven f(x) = x²+2x and g(x) = 2x
f(g(x)) = f(2x)
f(2x) = (2x)² + 2(2x)
f(2x) = 4x² + 4x
f(g(x)) = 4x² + 4x
f(g(2)) = 4(2)² + 4(2)
f(g(2)) = 16+8
f(g(2)) = 24
2) f(x) = x+1 and g(x) = 5x
f(g(x)) = f(5x)
f(5x)= 5x + 1
f(g(x)) = 5x + 1
f(g(-1)) = 5(-1) + 1
f(g(-1)) = -5+1
f(g(-1)) = -4
10m/s
32m/s
83m/s
None of these
Answer :
C
Solution :
At any instant x2+y2=52
Differentiating w.r.t. time 2xxdt+2ydydt=0
Here dxdt=2,dydt=u⇒u=83m/s
Domain is all real numbers.
Range is all real numbers geater than 0
