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3 years ago

Helppppppppppppp asap

Mathematics

2 answers:

zlopas [31]3 years ago

7 0

A which is 10 just count from house to the market

dezoksy [38]3 years ago

5 0

10. Good luck with your work

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What is the answer to this----->7/8-5/6

dlinn [17]

<span>7/8-5/6
Multiply until both fractions have the same common denominator.
21/24 - 20/24
Subtract the numerators but NOT the denominators.
Final Answer: 1/24</span>

3 0

4 years ago

Read 2 more answers

Debroah earns $10 per hour tutoring other students in math class. she earns versus the time that she tutors for. on the lines be

vesna_86 [32]

It represents that she tutored for 0 hours, and earned $0.

3 0

3 years ago

What is the equation of 30-20

serious [3.7K]

If you would like to calculate x = 30 - 20, you can do this like this:

x = 30 - 20
x = 10

The correct result would be x = 10.

7 0

3 years ago

Quick algebra 1 question for 10 points!

trasher [3.6K]

$m = m \\ \frac{97 - 68}{2 - 1} = \frac{134 - 97}{3 - 2} \\ 29 = 37 \\ this \: function \: is \: non \: linear$

<h3>Since the only two other options are quadratic and given that it must satisfy one of them i will assume the following general form of the function.</h3>

$f(1) = 68 \: \: \: f(2) = 97 \: \: \: \: f(3) = 134 \\ f(x) = ax {}^{2} + bx + c$

<h3>Substitute in the first function any point.</h3>

$f(1) = 68 \\ 7.8(1) {}^{2} - 2.9(1) + 67.1 = 68 \\ 7.8 - 2.9 + 67.1 = 68 \\ 72 = 68 \\ this \: is \: false$

<h3>I'm pretty sure something is wrong with the given</h3>

7 0

2 years ago

Two friends compete with each other and five other, equally good, violinists for first and second chair in an orchestra, in a bl

Darina [25.2K]

Answer: 0.0476

Step-by-step explanation:

Given : Two friends and 5 other people compete with each other for first and second chair in an orchestra.

Total people in this competition= 2+5=7

By permutation , Number of ways to arrange 7 people= 7!

Also, number of ways for two friends end up as first and second chair together= 2 × 5! [ 2 ways to arrange friends on first and second chair and 5! ways to arrange others]

I.e. Required probability = $\dfrac{2\times5!}{7!}$

$=\dfrac{2!\times5!}{7\times6\times5!}\\\\=\dfrac{1}{7\times3}\\\\=\dfrac{1}{21}\\\\=0.0476$

Hence, the probability that the two friends end up as first and second chair together = 0.0476

4 0

4 years ago