Answer:
1.Improve sanitation facilities by providing toilets and latrines that flush into a sewer or safe enclosure.
2.Promote good hygiene habits through education. ...
3.Implement rainwater harvesting systems to collect and store rainwater for drinking or recharging underground aquifers.
Answer:
The correct answer is Single Circular DNA Molecule.
Explanation:
A bacterial genome, which is the DNA that is found in bacteria collectively, is a double stranded circular DNA. So it has no start and end like double stranded helix DNA. The option D, which is "Single Circular DNA Molecule" is correct.
I hope this answer helps.
Answer:
The question to be asked an investigated when observing a structure under the microscope to determine whether it is living is if it has a nucleus if eukaryote or nucleoid if prokaryote.
Explanation:
The major organelle that must be present in all living cells is the nucleus or nucleoid and the protoplasm. The observation of the cell under the microscope will show the subcellular entity, nucleus/nucleoid, more pronounced than other organelles in the cell. The nucleus house the necessary information for the maintenance and reproduction, which is mainly the genetic information that dictates the translational protein products that are needed to build another aspect of the cells. Therefore, when such a tiny structure is placed under the light microscope under the view of oil immersion, the nucleus of the cell should be visible if it is a living structure.
Answer:
1/3
Explanation:
<em>A standard monohybrid cross is a cross that follows the dominance/recessive pattern from Mendel's experiment.</em>
It means the purple flower color is dominant over the white flower color.
Assuming the allele for purple flower color is P and that of the white flower color is p, a standard monohybrid cross will involve a true breeding PP and pp.
PP x pp: Pp, Pp, Pp and Pp. All the F1 offspring will have purple flowers with Pp genotype.
At F2: Pp x Pp = PP, Pp, Pp, and pp.
3/4 or 75% of the F2 offspring have purple flower color out of which 1 is true breeding for the trait.
Hence the fraction of the purple flowered peas in the F2 that is expected to be true-breeding (PP) is 1 out of 3.
