3 years ago

Find 5 consecutive even integers such that the largest is 12 less than twice the smallest.

Mathematics

2 answers:

alukav5142 [94]3 years ago

4 0

Answer:

10,8,6,4,2,

Step-by-step explanation:

it is all even

NemiM [27]3 years ago

3 0

X, x+2, x+4, x+6, x+8
Largest: x+8
Smallest: x
x+8 = 2x - 12
12+8 = x
x=20
Numbers: 20, 22, 24, 26, 28

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