If the dimensions were all the same number ... the box was a cube ...
then each dimension would be (the cube root of 13,800) cm.
∛13,800 = 23.986... (rounded)
so the place to look is around 23 .
(22 x 23 x 24) = 12,144 <== too small; go up one integer
(23 x 24 x 25) = 13,800 <== Eureka !
The consecutive integers are 23, 24, and 25 .
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
brainly.com/question/24369824
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