Answer:
C. 1/(x^2 +1) > 0
Step-by-step explanation:
The cube of a negative number is negative, eliminating choices B and D for certain negative values of x.
1/x^2 is undefined for x=0, so cannot be compared to zero.
The value 1/(x^2+1) is positive everywhere, so that is the expression you're looking for.
1/(x^2 +1) > 0
Answer:1/2m>50
Step-by-step explanation:Put a line under the sign.
If two lines are perpendicular, then their slopes have a product of -1 or you could say they are opposite signed reciprocals of each other.
The given equation has a slope of -3. We know this because it is in slope-intercept form y = mx + b ...y = (slope)x + (y-intercept).
so taking the slope -3...the opposite signed reciprocal would be +

Now we have a slope and a point... we can use them to find the b (y-intercept)
x = 4, y = 3, and m =



Using the common denominator fraction for 3, we subtract 4/3 from both sides


plug the values for m and b into the slope intercept form
Answer:

Step-by-step explanation:
Given:
The equation given is:

We simplify the given equation using the following law of indices:

Therefore,

Since the base on both the sides is same, therefore, their exponents must also be same. This gives,

Therefore, the value of 'n' is 3.
_2_
79/158 = 2
158
79x2= 158