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mezya [45]
3 years ago
8

gabys piggy bank contains nickles and dimes worth $5.15. If she has 66 coins in all, how many of each does she have

Mathematics
2 answers:
olasank [31]3 years ago
8 0

8.18

Step-by-step explanation:

8.18

pow pom wyh oqhw uwhwn 8.18 ge wk

seropon [69]3 years ago
6 0

Answer:

37 Dimes, 29 Nickels

Step-by-step explanation:

x= dimes

66-x = nickels

.1 (x) = dimes

.05 (66-x) = nickels

Solve

3.3 + 0.5x = 5.15

Solve again then you come out with

x= 37

66 - 37 = 29

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Bad White [126]

The formula for the perimeter of a square is P = 4s, where s is the length of one of the four (4) congruent sides of the square.

The formula for the area of a square is A = s², and we're given that the area of a square, whose perimeter we're trying to find, is 36 sq. units; therefore, we have:

A = s²

36 sq. units = s²

√(36 sq. units) = √s²

6 units = s (Note: We used the positive square root (6) rather than the negative square root (-6) since you physically can't have a negative length!)

Therefore, ...

P = 4s

P = 4(6 units)

P = 24 units is the perimeter of a square whose area is 36 square units

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3 years ago
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jolli1 [7]

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2. The integer is -4.

Solution:

To write an integer that represents the given situation:

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Here, the distance between ground and plane is mentioned.

Plane is above the ground. So, it is positive integer.

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Here, also mentioned the distance between surface of water to swimmer.

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7 0
3 years ago
Candice spent 5 1/4 hours doing her homework. Her brother, Ronald, spent 1/2 that number of hours doing his homework. How many h
ra1l [238]

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If staff salaries were $32,000/month last year and $47,000/month this year, what is the percentage labor cost increase
oksano4ka [1.4K]
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Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.
Ann [662]

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

7 0
3 years ago
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