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alexira [117]
3 years ago
6

Work out the value 4^2 x2^4

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0
64 is the answer ^the above explanation is correct
elixir [45]3 years ago
3 0

Answer

The answer to this equation would be 64. '^' just means multiplied by. It has the same mathematical definition as the multiplication sign.

Step-by-step explanation:

USING PEMDAS (NO PARENTHESES)

4 x 2 x 2 x 4

8 x 2 x 4

16 x 4

64

USING PEMDAS (WITH PARENTHESES)

(4 x 2) x (2 x 4)

(8) x (2 x 4)

(8) x (8)

64

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8x10to the 3rd power
asambeis [7]

Answer:

512000

Step-by-step explanation:

8*10

80*80*80

7 0
3 years ago
Read 2 more answers
What is three ratios that are equivalent to 18:4
musickatia [10]
We can make ratios equivalent to 18:4 by dividing and multiplying on it.
1. (18:4)/2=9:2
2. (18:4)*2=36:8
3. (18:4)*3=54:12

You're welcome :).
5 0
3 years ago
Read 2 more answers
The question is in photos
DedPeter [7]

Answer: 2535

Step-by-step explanation:

use order of operations (parenthesis, exponents, multiplication/division, addition/subtraction)

first ill handle the two innermost parenthesis

(4 + 3(2 - 8))

(4 + 3(-6))

(4 - 18)

-14

now lets move on to the next parenthesis

( 3 - 5^2(-14))

(3 - 25( - 14)

( 3 + 350)

353

now onto the last part of the problem

8^2 + 7 (353)

64 + 2471

2535 :))

3 0
3 years ago
Find the radius if mADB=270° and length is 61.26 meters
love history [14]

Given:

In the given circle, ∠ADB = 270° and length of ADB = 61.26 m

To find the radius of the circle.

Formula

The formula to determine the radius is given by

arc \ length =(\frac{\theta}{360})2 \pi r

Substituting arc length = 61.26, \theta= 270, we get;

61.26 =(\frac{270}{360})2 (3.14) r

61.26 =4.71 r

    13=r

Thus, the radius is 13 m

6 0
3 years ago
What is the inverse of f (x)=10-×^2
Bad White [126]
Finding the inverse function of

\mathsf{f(x)=10-x^2}


Remember that when you compose f with its inverse \mathsf{f^{-1}}, you'll get the identity function:

\mathsf{(f\circ f^{-1})(x)=x}\\\\ \mathsf{f\big[f^{-1}(x)\big]=x}\\\\


So if

\mathsf{f(x)=10-x^2}


then

\mathsf{f\big[f^{-1}(x)\big]=10-[f^{-1}(x)]^2}\\\\ \mathsf{x=10-[f^{-1}(x)]^2}\\\\ \mathsf{[f^{-1}(x)]^2=10-x}\\\\ \mathsf{f^{-1}(x)=\pm \sqrt{10-x}}\\\\ \mathsf{f^{-1}(x)=-\sqrt{10-x}~~~or~~~f^{-1}(x)=\sqrt{10-x}}


The sign of the inverse depends on the domain of \mathsf{f(x)} itself, and where it's invertible.


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2198197


I hope this helps.


Tags: <em>inverse function definition identity domain algebra</em>

3 0
3 years ago
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