Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
Answer:
e= -2
Step-by-step explanation:
1) distribute so you get 6+0.75e=2-1.25e
2) move the variable to one side so you get 6+2e=2
3) subtract the 6: 2e=-4
4) divide by 2: e= -2
Answer:
The simplest answer would just be 14:19
However the unsimplified answer is 1260:1710
Answer:
70
Step-by-step explanation:
56+25%=70 (:
