Let the length = x
2 lengths are 2x.
Then you have 400 - 2x for both widths, so the width is 200 - x.
The are if the rectangle is

y = x(200 - x)

y = 200x - x^2

y = -x^2 + 200x

Take the first derivative ans set equal to zero to find a maximum value.

y' = -2x + 200

-2x + 200 = 0

-2x = -200

x = 100

Since the side of the rectangle is 100, all sides measure 100 ft, and you have a square.
The maximum area is 100 ft * 100 ft = 10,000 ft.

3 0

4 years ago

PLZ ANSWER 20 POINTS

Nataliya [291]

B. but im not entirely sure

3 0

3 years ago

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The rectangle below has an area of x^2 - 6x - 7 square meters and a width of x - 7 meters.

monitta

Answer:

x+1 meters

Step-by-step explanation:

Area = Length * Width

x^2 - 6x - 7 = length * (x-7)

x^2 + x - 7x - 7 = length * ( x-7)

x*(x+1) - 7*(x+1) = length * (x-7)

(x-7)*(x+1) = length * (x-7)

x+1 = length [for (x-7) not equal 0]

6 0

3 years ago

A square has a side length of 7 centimeters. A circle has a diameter of 7 centimeters. What is true about the areas of the two f

Stels [109]

Answer: The area of the circle will be eleven-fourteenth of the area of square.

Step-by-step explanation: Given that a square has a side of length 7 cm and a circle has a diameter of 7 cm. We need to find the statement which is true about the areas of these two figures.

The area of the square will be

$S_a=7^2=49~\textup{cm}^2.$

And, the area of the circle will be

$C_a=\pi r^2=\pi \times \left(\dfrac{7}{2}\right)^2=\dfrac{\pi}{4}\times 49=\dfrac{22}{7\times 4}\times 49\\\\\Rightarrow C_a=\dfrac{11}{14}\times S_a.$

Thus, the area of the circle will be eleven-fourteenth of the areq of the square.

6 0

3 years ago

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