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LenaWriter [7]
4 years ago
5

Merl needs to cut down 10.5 trees for every 5 cabins she builds

Mathematics
1 answer:
Anika [276]4 years ago
7 0

10.5*5= 52.5 is the correct answer to the question

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Out of 100 cars on a used car lot, 20 cars have manual transmissions , 50 cars have air conditioning , and 8 cars have both .
slega [8]

Answer:  whats the question?

Step-by-step explanation:

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3 years ago
Simplify. Show your work.
alex41 [277]
1 5/6 is the correct answer.
8 0
4 years ago
Question : Find if the coordinates given lie on the circles below: (a) Does (4,2) lie on the circle with equation
lorasvet [3.4K]
Answer: No

Explanation

8 0
3 years ago
A piece of wood is divided into two pieces in the ratio of 2:5. One piece is 10 cm long so how long is the other piece?
klio [65]

Answer:

The length of the pother piece of the wood is 25 cm.

Step-by-step explanation:

Let the length of a piece of wood is x such that the ratio of two pieces is 2:5. Two pieces are 2x and 5 x

Length of the first piece is 10 cm. It means, 2x = 10 i.e. x = 5

We have considered that the length of other piece is 5x. It means 5×5 = 25 cm.

Hence, the length of the pother piece of the wood is 25 cm

8 0
3 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0
3 years ago
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