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Xelga [282]
3 years ago
5

Which equation represents the line that passes through (–8, 11) and (4, 7/2)?

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0
A is the answer since if you graph it, it has those points, or you may just simply plug in the x points that are given and see if they equal the y number
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The product of 15 and a number x is −75.
lesya [120]

Answer:

the solution is in the figure

the number is -5

7 0
3 years ago
Exponential Growth or Decay?
goldenfox [79]

Answer:

first one is decay

second one is growth

Step-by-step explanation:

4 0
4 years ago
Help asap please 40 points for help
GuDViN [60]

Answer:

a. connect the point (0 , 3) with A

b. connect the origin (0 , 0) with B

c. For A: y = 0.5x +3

For B: y = 0.5x

Step-by-step explanation:

y = ax + b is the general rule for any straight line

a being the slope and b being the y intercept, a is given to be 0.5

y = 0.5x + b, substitute the coordinates of point A

4 = 0.5 *2 +b hence b = 4 - 0.5 *2 = 4 - 1 = 3

so y = 0.5 x + 3 is the equation of the line passing through A

since the second line that passes through B is parallel to the first, hence it has the same slope of 0.5

same procedure, substitute coordinates of B

2 = 0.5 * 4 + b hence b = 2 - 0.5 *4 = 2 - 2= 0

so y = 0.5 x is the equation of the line passing through B

6 0
3 years ago
How do you solve what is 30% of $240
DerKrebs [107]
The Answer would be x=72. Why? Because \frac{x}{240} =  \frac{30}{100}.   Fraction  \frac{30}{100} is your %.  You Cross multiply 240 * 30 = 100x
240 time 30 = 7200. you want x to  be alone so you do 7200 divided by 100 equaling 72. So you get x=72. 
6 0
4 years ago
Y=4x-2tan(x), (-pi/2,pi/2)<br> which are the relative min and max?
Jlenok [28]

relative max  = pi -2

relative min   = -2 pi

Step-by-step explanation:

y= 4x- 2tan(x), (-pi/2,pi/2)

To find relative max and min,

According to mathematical procedure to find relative max and relative min,

the following procedure should be carry out.

Derivating equation with respect to x,

          \frac{dy}{dx} =\frac{d}{dx}  (4\times x -2 \times tan x).....(1)

Equating equation (1) to Zero,

We get,

           0 =\frac{d}{dy}  (4\times x -2 \times tan x)

           0 =  4 -2 \times sec^{2}  x

           4 = 2 \times sec^{2}  x

           2 = sec^{2}  x

           x= \frac{\pi }{4}....stationary point

There are total three points

1. -pi/2      2. pi/2      3. pi/4

checking local min and local max

first considering -pi/2;

                   \frac{d^{2}y  }{dx^{2} } =\frac{d^{2} }{dx^{2} }  (4\times x -2 \times tan x)...(2)

putting x= pi/4 in equation (2),

we get,      

                   \frac{d^{2}y  }{dx^{2} } = -4 <0      

So, we have local max at x=pi/4

by putting value of x in equation (1);

we get,

                 y =   4\times (\pi /4 ) -2 \times tan (\pi /4 )

                y = \pi - 2  .... is maximum point.

Similarly,  at  x= -pi/ 2,

                  \frac{d^{2}y  }{dx^{2} } = 1 >0

So, we have local min at x=-pi/2

by putting value of x in equation (1);

we get,

                 y =   4\times (-\pi /2 ) -2 \times tan (-\pi /2 )

                 y =  -2 \times \pi.... is minimum point

       

3 0
3 years ago
Read 2 more answers
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